If/else syntax on password verification in javascript -


i'm new javascript , trying list out characters missing failed password tell users need input.

window.onload = function() {    var info = document.getelementbyid("info");     var test = document.getelementbyid("myform").test;     test.onclick = function(e)    {      e.preventdefault();      var pw = document.getelementbyid("myform").pw.value;       var formula = /(?=.*[a-z])(?=.*[a-z])(?=.*[0-9]).{6,}/;       if(formula.test(pw))      {          document.getelementbyid("myform").submit();      }      else if pw.match(/\d/g) == null {         info.innerhtml = "you need number";         console.log(pw.match(/\d/g))       } else {         info.innerhtml = "you need number."      }       };  };

the above first run through of checking if user inputted password numbers. keep getting 

uncaught syntaxerror: unexpected identifier

in chrome dev tools pw.match portion underlined. i've looked elsewhere online , syntax looks correct. going wrong?

you need parentheses around condition of if block.

 else if (pw.match(/\d/g) == null) {     ...

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