bash - Need regex to remove a character in a datetime string in csv file -


i have csv file has following string:

"2016-10-25t14:07:49.298-07:00"

which replace with: 

"2016-10-25", "14:07:49"

i matched original string regular expression:

([0-9]{4}-[0-9]{2}-[0-9]{2})[t]([0-9]{2}\:[0-9]{2}\:[0-9]{2})\.[0-9]{3}-07\:00

but need help

with awk, assuming t , . unique

$ echo '"2016-10-25t14:07:49.298-07:00"' | awk -f'[t.]' '{print $1 "\", \"" $2 "\""}' "2016-10-25", "14:07:49"
  • -f'[t.]' assign t or . field separator
  • then print first , second field required formatting

-

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