ruby - Finding palindromes by adding its reversed to itself through x to y doing only depth number of calculation -

i'm having trouble doing challenge in ruby palindromes.

i looked many sources , think brain melted bit novice programmer.

lemme sum question :

so user beginning value ending value, , depth value.we take beginning value , check if number palindrome,if isn't add reversed itself( 20, reverse(20)=02, add , 22) , check number find if palindrome.if isn't take calculated number , add reversed itself.but can "depth" value times. , print if find palindrome through calculations print value ----> xxxx if not print value ----> special number.

i'm able find palindromes, through given , ending value.but cant implement depth thing.my problem looks lot setting limit on loops , calculating palindromes in c programming since i'm ruby novice cant make sense of c now.any appreciated.

edit : x y , beginning value ending value, if type 20 beginning , 30 ending value, check 20 if palindrome add reversed etc.once finish checking check next number, 21 22,23... 30.

def doit(n, max_tries)   max_tries.times.each     rev = n.to_s.reverse.to_i      (n == rev) ? (return n) : n += rev   end   nil end  doit(22,   1)   #=> 22  doit(21,   1)   #=> nil doit(21,   2)   #=> 33  doit(137,  1)   #=> nil doit(137,  2)   #=> 868  doit(1373, 2)   #=> nil  doit(1373, 3)   #=> 9119  doit(13732,  9) #=> nil  doit(13732, 10) #=> 134202431