Java: String index out of range while checking if a number is a palindrome -

so, in order check if number palindrome converted string. know there similar question on have checked solution, appreciated. why "exception in thread "main" java.lang.numberformatexception: ?

my code here;

/* (palindrome integer) write methods following headers  // return reversal of integer, i.e., reverse(456) returns 654 public static int reverse(int number)  // return true if number palindrome public static boolean ispalindrome(int number)  use reverse method implement ispalindrome. number palindrome if reversal same itself. write test program prompts user enter integer , reports whether integer palindrome. */  import java.util.scanner;  public class test {     public static void main(string[] args) {         system.out.println("please enter number");         scanner input = new scanner(system.in);         int number = input.nextint();         if (ispalindrome(number))             system.out.println("the number palindrome");         else             system.out.println("the number not palindrome");      }      public static int reverse(int number) {         string reverse = "";         string n = number + " ";         (int = n.length() - 1; >= 0; i--) {             reverse += n.charat(i);         }          return integer.parseint(reverse);     }      public static boolean ispalindrome(int number) {         return number == reverse(number) ? true : false;     } } 

the problem in reverse function. in fact instruction string n = number + " "; concatenation of value number blank string. not number , later on gives nomberformatexception @ instruction return integer.parseint(reverse); . should use string n = integer.tostring(number);

here's reviewed method

 public static int reverse(int number) {     string reverse = "";     string n = integer.tostring(number); // + " ";     system.out.println(reverse);     (int = n.length() - 1; >= 0; i--) {         reverse += n.charat(i);     }      return integer.parseint(reverse);  }