python - Removing items from list if argument is False -

my code check if time valid, returns list true , false, depends, want if it's false remove list.

here's code

def markvalid(s):         = []         if len(s) > 2:             if s[1] - s[0] > 0.1:                 a.append(true)             else:                 a.append(false)             in range(1, len(s) - 1):                 if s[i] - s[i - 1] < 0.1 or s[i + 1] - s[i] < 0.1:                     a.append(false)                 else:                     a.append(true)             if s[-1] - s[-2] > 0.1:                 a.append(true)             else:                 a.append(false)             return         if len(s) == 1:             return [true]         if len(s) == 2 , s[1] - s[0] > 0.1:             return [true, true]         else:             return [false, false] 

just don't append falses?

however if understand correctly, want filter input list, right? if case can use current function like

>>> test=[5.1, 5.6, 6.0, 10.34, 10.37, 10.45, 12.5] >>> markvalid(test) [true, true, true, false, false, false, true] >>> [x x,m in zip(test,markvalid(test)) if m] [5.1, 5.6, 6.0, 12.5] >>>  

if not case, here alternative filter

>>> [x x in markvalid(test) if x ] [true, true, true, true] >>>  

in case of filtering data can same effect original function instead of appending true append value in position i , nothing otherwise, , in others cases return original list or empty list accordingly, minor changes code

def filtervalid(s):     if len(s) > 2:         a=[]         if s[1] - s[0] > 0.1:             a.append(s[0])         in range(1, len(s) - 1):             if not( s[i] - s[i - 1] < 0.1 or s[i + 1] - s[i] < 0.1 ):                 a.append(s[i])         if s[-1] - s[-2] > 0.1:             a.append(s[-1])         return     if len(s) == 1:         return s     if len(s) == 2 , s[1] - s[0] > 0.1:         return s     return [] 

and testing it

>>> filtervalid(test) [5.1, 5.6, 6.0, 12.5] >>>