xml - In XSL, how can I print only the first line in for-each block? -

i made list of books in xml. following format of xml file; there more <book> blocks, of course.

<data>     <book>         <title>encyclopaedia britannica</title>         <category>encyclopedia</category>         <language>english</language>         <author>encyclopaedia britannica editorial</author>         <year>1768</year>         <price>49.99</price>     </book> </data> 

and want print title of expensive one. tried follows in .xsl file:

<p style = "display: block;">     expensive book "     <xsl:for-each select="data/book">         <xsl:sort select="price" order="descending"/>         <!-- <xsl:value-of select="title"/> -->     </xsl:for-each>         <xsl:value-of select="data/book/title"/>     " </p> 

when <xsl:value-of> block in <xsl:for-each>(which set comment) executed prints books sorted in descending order. of course, <xsl:value-of select="data/book/title"/> makes first book of original table printed.

so want print expensive 1 stopping printing other books first 1 when table sorted.

i know there's no such thing break, thought using <xsl:if> block check if row first or not. idea possible? or can in way?

so thought using <xsl:if> block check if row first or not.

yes, correct idea:

<xsl:for-each select="/data/book">     <xsl:sort select="price" data-type="number" order="descending"/>     <xsl:if test="position()=1">         <xsl:value-of select="title"/>     </xsl:if> </xsl:for-each> 

note selects first expensive title in case of tie.

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or can in way?

that depends on xslt processor use. in xslt 2.0, can use max() function. , several xslt 1.0 processors support math:max() , math:highest() extension functions.